F(24)=50(1/2)^n-1

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Solution for F(24)=50(1/2)^n-1 equation: 



(24)=50(1/2)^F-1

We move all terms to the left:

(24)-(50(1/2)^F-1)=0



Domain of the equation: 2)^F-1)!=0

F!=0/1

F!=0

F∈R



We add all the numbers together, and all the variables

-(50(+1/2)^F-1)+24=0

We multiply all the terms by the denominator


-(50(+1+24*2)^F-1)=0



We calculate terms in parentheses: -(50(+1+24*2)^F-1), so:

50(+1+24*2)^F-1

We add all the numbers together, and all the variables

5049^F-1

Back to the equation:

-(5049^F-1)



We get rid of parentheses

-5049^F+1=0

We move all terms containing F to the left, all other terms to the right

-5049^F=-1

F=-1/1

F=-1

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